2x^2y-8y=

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Solution for 2x^2y-8y= equation: 


Simplifying
2x2y + -8y = 0

Solving
2x2y + -8y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8y' to each side of the equation.
2x2y + -8y + 8y = 0 + 8y

Combine like terms: -8y + 8y = 0
2x2y + 0 = 0 + 8y
2x2y = 0 + 8y
Remove the zero:
2x2y = 8y

Divide each side by '2y'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}

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